int compareTo(num other)

Compares this to `other`.

Returns a negative number if `this` is less than `other`, zero if they are equal, and a positive number if `this` is greater than `other`.

The orderding represented by this method is a total ordering of num values. All distinct doubles are non-equal, as are all distinct integers, but integers are equal to doubles if they have the same numerical value.

For doubles, the `compareTo` operation is different from the partial ordering given by `operator==`, `operator<` and `operator>`. For example, IEEE doubles impose that `0.0 == -0.0` and all comparison operations on NaN return false.

This function imposes a complete ordering for doubles. When using `compareTo` the following properties hold:

• All NaN values are considered equal, and greater than any numeric value.
• -0.0 is less than 0.0 (and the integer 0), but greater than any non-zero negative value.
• Negative infinity is less than all other values and positive infinity is greater than all non-NaN values.
• All other values are compared using their numeric value.

Examples:

``````print(1.compareTo(2)); // => -1
print(2.compareTo(1)); // => 1
print(1.compareTo(1)); // => 0

// The following comparisons yield different results than the
// corresponding comparison operators.
print((-0.0).compareTo(0.0));  // => -1
print(double.NAN.compareTo(double.NAN));  // => 0
print(double.INFINITY.compareTo(double.NAN)); // => -1

// -0.0, and NaN comparison operators have rules imposed by the IEEE
// standard.
print(-0.0 == 0.0); // => true
print(double.NAN == double.NAN);  // => false
print(double.INFINITY < double.NAN);  // => false
print(double.NAN < double.INFINITY);  // => false
print(double.NAN == double.INFINITY);  // => false
``````

## Source

`int compareTo(num other);`