indexWhere method Null safety

int indexWhere(
  1. bool test(
    1. E element
    ),
  2. [int start = 0]
)
override

The first index in the list that satisfies the provided test.

Searches the list from index start to the end of the list. The first time an object o is encountered so that test(o) is true, the index of o is returned.

final notes = <String>['do', 're', 'mi', 're'];
final first = notes.indexWhere((note) => note.startsWith('r')); // 1
final second = notes.indexWhere((note) => note.startsWith('r'), 2); // 3

Returns -1 if element is not found.

final notes = <String>['do', 're', 'mi', 're'];
final index = notes.indexWhere((note) => note.startsWith('k')); // -1

Implementation

int indexWhere(bool test(E element), [int start = 0]) {
  if (start < 0) start = 0;
  for (int i = start; i < this.length; i++) {
    if (test(this[i])) return i;
  }
  return -1;
}