LinkedHashSet<E> constructor
Create an insertion-ordered hash set using the provided
equals
and hashCode
.
The provided equals
must define a stable equivalence relation, and
hashCode
must be consistent with equals
.
If you supply one of equals
and hashCode
,
you should generally also supply the other.
Some equals
or hashCode
functions might not work for all objects.
If isValidKey
is supplied, it's used to check a potential element
which is not necessarily an instance of E
, like the argument to
contains which is typed as Object?
.
If isValidKey
returns false
, for an object, the equals
and
hashCode
functions are not called, and no key equal to that object
is assumed to be in the map.
The isValidKey
function defaults to just testing if the object is an
instance of E
, which means that:
LinkedHashSet<int>(equals: (int e1, int e2) => (e1 - e2) % 5 == 0,
hashCode: (int e) => e % 5);
does not need an isValidKey
argument, because it defaults to only
accepting int
values which are accepted by both equals
and hashCode
.
If neither equals
, hashCode
, nor isValidKey
are provided,
the default isValidKey
instead accepts all values.
The default equality and hashcode operations are assumed to work on all
objects.
Likewise, if equals
is identical, hashCode
is identityHashCode
and isValidKey
is omitted, the resulting set is identity based,
and the isValidKey
defaults to accepting all keys.
Such a map can be created directly using LinkedHashSet.identity.
Implementation
external factory LinkedHashSet(
{bool Function(E, E)? equals,
int Function(E)? hashCode,
bool Function(dynamic)? isValidKey});