operator == abstract method

Test whether another object is equal to this function.

Function objects are only equal to other function objects (an object satisfying object is Function), and never to non-function objects.

Some function objects are considered equal by == because they are recognized as representing the "same function":

• It is the same object. Static and top-level functions are compile time constants when used as values, so referring to the same function twice always yields the same object, as does referring to a local function declaration twice in the same scope where it was declared.

  void main() {
    assert(identical(print, print));
    int add(int x, int y) => x + y;
    assert(identical(add, add));
  }
  

• The functions are same member method extracted from the same object. Repeatedly extracting ("tearing off") the same instance method of the same object to a function value gives equal, but not necessarily identical, function values.

  var o = Object();
  assert(o.toString == o.toString);
  

• Instantiations of equal generic functions with the same types yields equal results.

  T id<T>(T value) => value;
  assert(id<int> == id<int>);
  

  (If the function is a constant and the type arguments are known at compile-time, the results may also be identical.)

Different evaluations of function literals are not guaranteed or required to give rise to identical or equal function objects. For example:

var functions = <Function>[];
for (var i = 0; i < 2; i++) {
  functions.add((x) => x);
}
print(identical(functions[0], functions[1])); // 'true' or 'false'
print(functions[0] == functions[1]); // 'true' or 'false'

If the distinct values are identical, they are always equal.

If the function values are equal, they are guaranteed to behave indistinguishably for all arguments.

If two functions values behave differently, they are never equal or identical.

The reason to not require a specific equality or identity of the values of a function expression is to allow compiler optimizations. If a function expression does not depend on surrounding variables, an implementation can safely be shared between multiple evaluations. For example:

List<int> ints = [6, 2, 5, 1, 4, 3];
ints.sort((x, y) => x - y);
print(ints);

A compiler can convert the closure (x, y) => x - y into a top-level function.