int lastIndexOf(
E element,
[int start]
)

Returns the last index of element in this list.

Searches the list backwards from index start to 0.

The first time an object o is encountered so that o == element, the index of o is returned.

List<String> notes = ['do', 're', 'mi', 're'];
notes.lastIndexOf('re', 2); // 1

If start is not provided, this method searches from the end of the list./Returns

notes.lastIndexOf('re');  // 3

Returns -1 if element is not found.

notes.lastIndexOf('fa');  // -1

Source

/**
 * Returns the last index of [element] in this list.
 *
 * Searches the list backwards from index [start] to 0.
 *
 * The first time an object [:o:] is encountered so that [:o == element:],
 * the index of [:o:] is returned.
 *
 *     List<String> notes = ['do', 're', 'mi', 're'];
 *     notes.lastIndexOf('re', 2); // 1
 *
 * If [start] is not provided, this method searches from the end of the
 * list./Returns
 *
 *     notes.lastIndexOf('re');  // 3
 *
 * Returns -1 if [element] is not found.
 *
 *     notes.lastIndexOf('fa');  // -1
 */
int lastIndexOf(E element, [int start]);