int times
) Creates a new string by concatenating this string with itself a number of times.
The result of str * n is equivalent to
str + str + ...(n times)... + str.
Returns an empty string if times is zero or negative.
Source
/**
* Creates a new string by concatenating this string with itself a number
* of times.
*
* The result of `str * n` is equivalent to
* `str + str + ...`(n times)`... + str`.
*
* Returns an empty string if [times] is zero or negative.
*/
String operator *(int times);