# replaceRange abstract method

Replaces a range of elements with the elements of `replacements`

.

Removes the objects in the range from `start`

to `end`

,
then inserts the elements of `replacements`

at `start`

.

```
final numbers = <int>[1, 2, 3, 4, 5];
final replacements = [6, 7];
numbers.replaceRange(1, 4, replacements);
print(numbers); // [1, 6, 7, 5]
```

The provided range, given by `start`

and `end`

, must be valid.
A range from `start`

to `end`

is valid if 0 ≤ `start`

≤ `end`

≤ length.
An empty range (with `end == start`

) is valid.

The operation `list.replaceRange(start, end, replacements)`

is roughly equivalent to:

```
final numbers = <int>[1, 2, 3, 4, 5];
numbers.removeRange(1, 4);
final replacements = [6, 7];
numbers.insertAll(1, replacements);
print(numbers); // [1, 6, 7, 5]
```

but may be more efficient.

The list must be growable.
This method does not work on fixed-length lists, even when `replacements`

has the same number of elements as the replaced range. In that case use
setRange instead.

## Implementation

`void replaceRange(int start, int end, Iterable<E> replacements);`