tryParse method Null safety

int? tryParse(
  1. String source,
  2. {int? radix}
)
override

Parse source as a, possibly signed, integer literal.

Like parse except that this function returns null where a similar call to parse would throw a FormatException.

Example:

print(int.tryParse('2021')); // 2021
print(int.tryParse('1f')); // null
// From binary (base 2) value.
print(int.tryParse('1100', radix: 2)); // 12
print(int.tryParse('00011111', radix: 2)); // 31
print(int.tryParse('011111100101', radix: 2)); // 2021
// From octal (base 8) value.
print(int.tryParse('14', radix: 8)); // 12
print(int.tryParse('37', radix: 8)); // 31
print(int.tryParse('3745', radix: 8)); // 2021
// From hexadecimal (base 16) value.
print(int.tryParse('c', radix: 16)); // 12
print(int.tryParse('1f', radix: 16)); // 31
print(int.tryParse('7e5', radix: 16)); // 2021
// From base 35 value.
print(int.tryParse('y1', radix: 35)); // 1191 == 34 * 35 + 1
print(int.tryParse('z1', radix: 35)); // null
// From base 36 value.
print(int.tryParse('y1', radix: 36)); // 1225 == 34 * 36 + 1
print(int.tryParse('z1', radix: 36)); // 1261 == 35 * 36 + 1

Implementation

external static int? tryParse(String source, {int? radix});